(x+7)(2x-1)=11x-3x^2

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Solution for (x+7)(2x-1)=11x-3x^2 equation: 


Simplifying
(x + 7)(2x + -1) = 11x + -3x2

Reorder the terms:
(7 + x)(2x + -1) = 11x + -3x2

Reorder the terms:
(7 + x)(-1 + 2x) = 11x + -3x2

Multiply (7 + x) * (-1 + 2x)
(7(-1 + 2x) + x(-1 + 2x)) = 11x + -3x2
((-1 * 7 + 2x * 7) + x(-1 + 2x)) = 11x + -3x2
((-7 + 14x) + x(-1 + 2x)) = 11x + -3x2
(-7 + 14x + (-1 * x + 2x * x)) = 11x + -3x2
(-7 + 14x + (-1x + 2x2)) = 11x + -3x2

Combine like terms: 14x + -1x = 13x
(-7 + 13x + 2x2) = 11x + -3x2

Solving
-7 + 13x + 2x2 = 11x + -3x2

Solving for variable 'x'.

Reorder the terms:
-7 + 13x + -11x + 2x2 + 3x2 = 11x + -3x2 + -11x + 3x2

Combine like terms: 13x + -11x = 2x
-7 + 2x + 2x2 + 3x2 = 11x + -3x2 + -11x + 3x2

Combine like terms: 2x2 + 3x2 = 5x2
-7 + 2x + 5x2 = 11x + -3x2 + -11x + 3x2

Reorder the terms:
-7 + 2x + 5x2 = 11x + -11x + -3x2 + 3x2

Combine like terms: 11x + -11x = 0
-7 + 2x + 5x2 = 0 + -3x2 + 3x2
-7 + 2x + 5x2 = -3x2 + 3x2

Combine like terms: -3x2 + 3x2 = 0
-7 + 2x + 5x2 = 0

Factor a trinomial.
(-7 + -5x)(1 + -1x) = 0


Subproblem 1
Set the factor '(-7 + -5x)' equal to zero and attempt to solve:

Simplifying
-7 + -5x = 0

Solving
-7 + -5x = 0

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + -5x = 0 + 7

Combine like terms: -7 + 7 = 0
0 + -5x = 0 + 7
-5x = 0 + 7

Combine like terms: 0 + 7 = 7
-5x = 7

Divide each side by '-5'.
x = -1.4

Simplifying
x = -1.4

Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {-1.4, 1}

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